What are the solutions to the equation x^2-15x=-54 ?

The solutions to the equation x^2-15x=-54 are x=9,x=6

Find the zeros of x^2-15x=-54

The zeros of x^2-15x=-54 are x=9,x=6

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x^{2} - 15 x = - 54

x = 9, x = 6

Solution steps

x^{2} - 15 x = - 54

Move

54

to the left side

x^{2} - 15 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 54 = 3

x_{1, 2} = \frac{- ( - 15 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 3}{2 \cdot 1}

x = \frac{- ( - 15 ) + 3}{2 \cdot 1} : 9

x = \frac{- ( - 15 ) - 3}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 9, x = 6

5 > 2 - x

2 (3 x + 8) = 70

x^{2} + 3 = 0

\frac{n ^{\frac{3}{5}}}{n - \frac{3}{4}}

- 5 x + 6 = - 12 x + 62

What are the solutions to the equation x^2-15x=-54 ?
The solutions to the equation x^2-15x=-54 are x=9,x=6
Find the zeros of x^2-15x=-54
The zeros of x^2-15x=-54 are x=9,x=6