What are the solutions to the equation -5x^2+3x-4=0 ?

The solutions to the equation -5x^2+3x-4=0 are x= 3/10-i(sqrt(71))/(10),x= 3/10+i(sqrt(71))/(10)

Find the zeros of -5x^2+3x-4=0

The zeros of -5x^2+3x-4=0 are x= 3/10-i(sqrt(71))/(10),x= 3/10+i(sqrt(71))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 5 x^{2} + 3 x - 4 = 0

x = \frac{3}{10} - i \frac{71}{10}, x = \frac{3}{10} + i \frac{71}{10}

Solution steps

- 5 x^{2} + 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 5 ) ( - 4 )}{2 ( - 5 )}

Simplify

3^{2} - 4 (- 5) (- 4) : 71 i

x_{1, 2} = \frac{- 3 \pm 71 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 3 + 71 i}{2 ( - 5 )}, x_{2} = \frac{- 3 - 71 i}{2 ( - 5 )}

x = \frac{- 3 + 71 i}{2 ( - 5 )} : \frac{3}{10} - i \frac{71}{10}

x = \frac{- 3 - 71 i}{2 ( - 5 )} : \frac{3}{10} + i \frac{71}{10}

The solutions to the quadratic equation are:

x = \frac{3}{10} - i \frac{71}{10}, x = \frac{3}{10} + i \frac{71}{10}

4 x^{2} + 10 x - 6

6 x - 54 = 3 x + 15

x^{2} y^{4} - y

9 - 2 x - x^{2} = 0

\frac{x ^{2} + x - 42}{x} \geq 0

What are the solutions to the equation -5x^2+3x-4=0 ?
The solutions to the equation -5x^2+3x-4=0 are x= 3/10-i(sqrt(71))/(10),x= 3/10+i(sqrt(71))/(10)
Find the zeros of -5x^2+3x-4=0
The zeros of -5x^2+3x-4=0 are x= 3/10-i(sqrt(71))/(10),x= 3/10+i(sqrt(71))/(10)