What is (\sqrt[5]{a^{-4}b^7})^2 ?

The solution to (\sqrt[5]{a^{-4}b^7})^2 is (b^2\sqrt[5]{b^4})/(a\sqrt[5]{a^3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (\sqrt[5]{a^{-4}b^7})^2

simplify

Solution steps

Simplify

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

Simplify

= \frac{b ^{\frac{14}{5}}}{a ^{\frac{8}{5}}}

Combine same powers :

Apply radical rule:

assuming

a \geq 0, b \geq 0

Simplify

- e^{- (- 1)}

((- 3)^{3})^{3}

1.2 \cdot 1 0^{- 7}

0.41 \times 1 0^{(- 3)} \times 22 \times 100

What is (\sqrt[5]{a^{-4}b^7})^2 ?
The solution to (\sqrt[5]{a^{-4}b^7})^2 is (b^2\sqrt[5]{b^4})/(a\sqrt[5]{a^3)}