What is B^1(1.1)yB^2(-1.7) ?

The solution to B^1(1.1)yB^2(-1.7) is -1.87yB^3

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simplify B^1(1.1)yB^2(-1.7)

simplify

B^{1} (1.1) y B^{2} (- 1.7)

- 1.87 y B^{3}

Solution steps

B^{1} (1.1) y B^{2} (- 1.7)

Apply rule:

(a) = a

(1.1) = 1.1

= B^{1} \cdot 1.1 y B^{2} (- 1.7)

Multiply the numbers:

1.1 (- 1.7) = - 1.87

= B^{1} (- 1.87) y B^{2}

Simplify

B^{1} B^{2} : B^{3}

= B^{3} (- 1.87) y

Remove parentheses:

B^{3} (- 1.87) y = - B^{3} \cdot 1.87 y

= - B^{3} \cdot 1.87 y

= - 1.87 y B^{3}

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