What are the solutions to the equation x^2=7x+30 ?

The solutions to the equation x^2=7x+30 are x=10,x=-3

Find the zeros of x^2=7x+30

The zeros of x^2=7x+30 are x=10,x=-3

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x^{2} = 7 x + 30

x = 10, x = - 3

Solution steps

x^{2} = 7 x + 30

Move

30

to the left side

x^{2} - 30 = 7 x

Move

7 x

to the left side

x^{2} - 30 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 7 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 30) = 13

x_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 1}

x = \frac{- ( - 7 ) + 13}{2 \cdot 1} : 10

x = \frac{- ( - 7 ) - 13}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 10, x = - 3

- 16 t^{2} + 80 t + 32 = 0

\frac{6 n}{5} + \frac{1}{2} = \frac{9 n - 1}{10}

0. 5^{\frac{1}{3}}

\frac{a ^{2} b ^{- 7}}{a ^{- 4} b ^{- 2}}

(\frac{1}{16})^{\frac{1}{4}}

What are the solutions to the equation x^2=7x+30 ?
The solutions to the equation x^2=7x+30 are x=10,x=-3
Find the zeros of x^2=7x+30
The zeros of x^2=7x+30 are x=10,x=-3