What is (3n^{1/4})(2n^{1/4}) ?

The solution to (3n^{1/4})(2n^{1/4}) is 6n^{1/2}

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simplify (3n^{1/4})(2n^{1/4})

simplify

(3 n^{\frac{1}{4}}) (2 n^{\frac{1}{4}})

6 n^{\frac{1}{2}}

Solution steps

(3 n^{\frac{1}{4}}) (2 n^{\frac{1}{4}})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

n^{\frac{1}{4}} n^{\frac{1}{4}} = n^{\frac{1}{4} + \frac{1}{4}}

= 3 \cdot 2 n^{\frac{1}{4} + \frac{1}{4}}

Combine the fractions

\frac{1}{4} + \frac{1}{4} : \frac{1}{2}

= 3 \cdot 2 n^{\frac{1}{2}}

Multiply the numbers:

3 \cdot 2 = 6

= 6 n^{\frac{1}{2}}

- 2.26 \cdot \frac{1 0 ^{- 19}}{1.6} \cdot 1 0^{- 19}

(61)^{2}

(x - 1)^{2} (x - 3)^{2} (x + 4)^{2}

(6.674 \cdot 1 0^{- 11}) (6 \cdot 1 0^{24})