What is x(x^2-3x+2)^2(x-7)^2 ?

The solution to x(x^2-3x+2)^2(x-7)^2 is x(x-7)^2(x^2-3x+2)^2

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simplify x(x^2-3x+2)^2(x-7)^2

simplify

x (x^{2} - 3 x + 2)^{2} (x - 7)^{2}

x (x - 7)^{2} (x^{2} - 3 x + 2)^{2}

Solution steps

x (x^{2} - 3 x + 2)^{2} (x - 7)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} - 3 x + 2)^{2} (x - 7)^{2} = ((x^{2} - 3 x + 2) (x - 7))^{2}

= x ((x^{2} - 3 x + 2) (x - 7))^{2}

((x^{2} - 3 x + 2) (x - 7))^{2} = (x^{2} - 3 x + 2)^{2} (x - 7)^{2}

= x (x^{2} - 3 x + 2)^{2} (x - 7)^{2}

3.6 \cdot 1 0^{- 8}

10 x y e^{- (x^{2} + y^{2})}

3.6 \cdot 1 0^{- 7}

t e^{- t} u (- t)

e^{- l n (x^{3})}

What is x(x^2-3x+2)^2(x-7)^2 ?
The solution to x(x^2-3x+2)^2(x-7)^2 is x(x-7)^2(x^2-3x+2)^2