What is the extreme e^{-0.06x}(2000+300x) ?

The extreme e^{-0.06x}(2000+300x) is Maximum(10,2744.05818…)

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extreme e^{-0.06x}(2000+300x)

extreme points

e^{- 0.06 x} (2000 + 300 x)

Maximum (10, 2744.05818 \dots)

Solution steps

f^{'} (x) = - 18 e^{- 0.06 x} (x - 10)

Find intervals:

Increasing

: - \infty < x < 10,

Decreasing

: 10 < x < \infty

Plug

x = 10

into

e^{- 0.06 x} (2000 + 300 x) : 2744.05818 \dots

Maximum (10, 2744.05818 \dots)

\frac{d}{d t} ((x) (c t e^{- \frac{b}{2 m} t}))

2.18 \cdot 1 0^{- 18} (3^{2}) (\frac{1}{4 ^{2}} - \frac{1}{6 ^{2}})

\frac{1}{2} (x^{2} + 1)^{- \frac{1}{2}} (2 x)

e^{- l n (x)} x

e^{- 2} \cdot 2^{0} \cdot \frac{1}{0 !} \cdot 0.125

What is the extreme e^{-0.06x}(2000+300x) ?
The extreme e^{-0.06x}(2000+300x) is Maximum(10,2744.05818…)