What is 2.18*10^{-18}(3^2)(1/(4^2)-1/(6^2)) ?

The solution to 2.18*10^{-18}(3^2)(1/(4^2)-1/(6^2)) is (109)/(10^{18)*160}

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simplify 2.18*10^{-18}(3^2)(1/(4^2)-1/(6^2))

simplify

2.18 \cdot 1 0^{- 18} (3^{2}) (\frac{1}{4 ^{2}} - \frac{1}{6 ^{2}})

\frac{109}{1 0 ^{18} \cdot 160}

Decimal Notation

6.8125 E - 19

Solution steps

2.18 \cdot 1 0^{- 18} (3^{2}) (\frac{1}{4 ^{2}} - \frac{1}{6 ^{2}})

Apply rule:

(a) = a

(3^{2}) = 3^{2}

= 2.18 \cdot 1 0^{- 18} \cdot 3^{2} (\frac{1}{4 ^{2}} - \frac{1}{6 ^{2}})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 18} = \frac{1}{1 0 ^{18}}

= 2.18 \cdot \frac{1}{1 0 ^{18}} \cdot 3^{2} (\frac{1}{4 ^{2}} - \frac{1}{6 ^{2}})

3^{2} = 9

= 2.18 \cdot \frac{1}{1 0 ^{18}} \cdot 9 (\frac{1}{4 ^{2}} - \frac{1}{6 ^{2}})

\frac{1}{4 ^{2}} - \frac{1}{6 ^{2}} = \frac{5}{144}

= 2.18 \cdot \frac{1}{1 0 ^{18}} \cdot 9 \cdot \frac{5}{144}

Multiply the numbers:

2.18 \cdot 9 = 19.62

= 19.62 \cdot \frac{1}{1 0 ^{18}} \cdot \frac{5}{144}

= \frac{5}{144} \cdot 19.62 \cdot \frac{1}{1 0 ^{18}}

19.62 = \frac{981}{50}

= \frac{5}{144} \cdot \frac{981}{50} \cdot \frac{1}{1 0 ^{18}}

\frac{5}{144} \cdot \frac{981}{50} \cdot \frac{1}{1 0 ^{18}} = \frac{109}{1 0 ^{18} \cdot 160}

= \frac{109}{1 0 ^{18} \cdot 160}

\frac{1}{2} (x^{2} + 1)^{- \frac{1}{2}} (2 x)

e^{- l n (x)} x

e^{- 2} \cdot 2^{0} \cdot \frac{1}{0 !} \cdot 0.125

(- 3 e^{- 2 (t - x)} + 10 e^{- t + x}) \cdot e^{- 2 x}

(- 1)^{n} \cdot 3^{n}

What is 2.18*10^{-18}(3^2)(1/(4^2)-1/(6^2)) ?
The solution to 2.18*10^{-18}(3^2)(1/(4^2)-1/(6^2)) is (109)/(10^{18)*160}