What is 12te^{-3(t-4)}u(t-4) ?

The solution to 12te^{-3(t-4)}u(t-4) is (12tu(t-4))/(e^{3(t-4))}

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simplify 12te^{-3(t-4)}u(t-4)

simplify

12 t e^{- 3 (t - 4)} u (t - 4)

\frac{12 t u ( t - 4 )}{e ^{3 (t - 4)}}

Solution steps

12 t e^{- 3 (t - 4)} u (t - 4)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 12 \cdot \frac{1}{e ^{3 (t - 4)}} t u (t - 4)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 12 t u ( t - 4 )}{e ^{3 (t - 4)}}

Multiply the numbers:

1 \cdot 12 = 12

= \frac{12 t u ( t - 4 )}{e ^{3 (t - 4)}}

(x + 5) (x + 5)

9 \times 1 0^{- 9}

e^{x} e^{- 3 x}

P^{1} (- 3, - 8) P^{2} (- 6, - 4)

What is 12te^{-3(t-4)}u(t-4) ?
The solution to 12te^{-3(t-4)}u(t-4) is (12tu(t-4))/(e^{3(t-4))}