What is log_{10}(x)-1/2 log_{10}(y)+7log_{10}(z) ?

The solution to log_{10}(x)-1/2 log_{10}(y)+7log_{10}(z) is log_{10}((xz^7sqrt(y))/y)

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simplify log_{10}(x)-1/2 log_{10}(y)+7log_{10}(z)

simplify

lo g_{10} (x) - \frac{1}{2} lo g_{10} (y) + 7 lo g_{10} (z)

lo g_{10} (\frac{x z ^{7} y}{y})

Solution steps

lo g_{10} (x) - \frac{1}{2} lo g_{10} (y) + 7 lo g_{10} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{1}{2} lo g_{10} (y) = lo g_{10} (y^{\frac{1}{2}})

= lo g_{10} (x) - lo g_{10} (y^{\frac{1}{2}}) + 7 lo g_{10} (z)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (x) - lo g_{10} (y^{\frac{1}{2}}) = lo g_{10} (\frac{x}{y ^{\frac{1}{2}}})

= lo g_{10} (\frac{x}{y ^{\frac{1}{2}}}) + 7 lo g_{10} (z)

Simplify

\frac{x}{y ^{\frac{1}{2}}} : \frac{x y}{y}

= lo g_{10} (\frac{x y}{y}) + 7 lo g_{10} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

7 lo g_{10} (z) = lo g_{10} (z^{7})

= lo g_{10} (\frac{x y}{y}) + lo g_{10} (z^{7})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (\frac{x y}{y}) + lo g_{10} (z^{7}) = lo g_{10} (\frac{x y}{y} z^{7})

= lo g_{10} (\frac{x y}{y} z^{7})

Simplify

\frac{x y}{y} z^{7} : \frac{x z ^{7} y}{y}

= lo g_{10} (\frac{x z ^{7} y}{y})

3 ln (x) + 2 ln (y) - 4 ln (z)

lo g_{10} (\frac{x ^{3}}{2})

lo g_{11} (11 x)

lo g_{7} (\frac{3 x}{2})

\frac{5}{2} ln (\frac{15}{2})

What is log_{10}(x)-1/2 log_{10}(y)+7log_{10}(z) ?
The solution to log_{10}(x)-1/2 log_{10}(y)+7log_{10}(z) is log_{10}((xz^7sqrt(y))/y)