What is factor 5b^2+21b+4 ?

The solution to factor 5b^2+21b+4 is (5b+1)(b+4)

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factor 5b^2+21b+4

factor

5 b^{2} + 21 b + 4

(5 b + 1) (b + 4)

Solution steps

5 b^{2} + 21 b + 4

Break the expression into groups

= (5 b^{2} + b) + (20 b + 4)

Factor out

b

from

5 b^{2} + b : b (5 b + 1)

Factor out

4

from

20 b + 4 : 4 (5 b + 1)

= b (5 b + 1) + 4 (5 b + 1)

Factor out common term

5 b + 1

= (5 b + 1) (b + 4)

9^{\frac{5}{2}}

(f^{- 3} g^{5} h^{8})^{- 3}

\frac{( - 6 ) - 4}{( - 6 ) ^{2} - 16}

10 h + 12 = 8 h + 4

5 x^{2} - 3 x - 2 \leq 0