What is log_{10}((2x)/y) ?

The solution to log_{10}((2x)/y) is log_{10}(2)+log_{10}(x)-log_{10}(y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}((2x)/y)

simplify

lo g_{10} (\frac{2 x}{y})

lo g_{10} (2) + lo g_{10} (x) - lo g_{10} (y)

Solution steps

lo g_{10} (\frac{2 x}{y})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{2 x}{y}) = lo g_{10} (2 x) - lo g_{10} (y)

= lo g_{10} (2 x) - lo g_{10} (y)

Simplify

lo g_{10} (2 x) : lo g_{10} (2) + lo g_{10} (x)

= lo g_{10} (2) + lo g_{10} (x) - lo g_{10} (y)

- lo g_{10} (6.2 \cdot 1 0^{- 10})

lo g_{4} (x^{5}) - lo g_{4} (x^{3})

3 ln (x) - \frac{2}{3} ln (x + 1) + ln (y) - 3 ln (z)

3 lo g_{7} (2 x) - 2 lo g_{7} (3 y)

\frac{1}{2} lo g_{2} (6) - 2 lo g_{2} (5)

What is log_{10}((2x)/y) ?
The solution to log_{10}((2x)/y) is log_{10}(2)+log_{10}(x)-log_{10}(y)