What is ln((s^2+1)/((s-1)^2)) ?

The solution to ln((s^2+1)/((s-1)^2)) is ln(s^2+1)-2ln(s-1)

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simplify ln((s^2+1)/((s-1)^2))

simplify

ln (\frac{s ^{2} + 1}{( s - 1 ) ^{2}})

ln (s^{2} + 1) - 2 ln (s - 1)

Solution steps

ln (\frac{s ^{2} + 1}{( s - 1 ) ^{2}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{s ^{2} + 1}{( s - 1 ) ^{2}}) = ln (s^{2} + 1) - ln ((s - 1)^{2})

= ln (s^{2} + 1) - ln ((s - 1)^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln ((s - 1)^{2}) = 2 ln (s - 1)

= ln (s^{2} + 1) - 2 ln (s - 1)

ln (9) + ln (x) + ln (y)

lo g_{10} (2 x + 7) - lo g_{10} (x)

ln (x) + ln (x + 2)

lo g_{2} (7 x)

lo g_{b} (y^{7} z)

What is ln((s^2+1)/((s-1)^2)) ?
The solution to ln((s^2+1)/((s-1)^2)) is ln(s^2+1)-2ln(s-1)