What are the solutions to the equation 1-4y^2=0 ?

The solutions to the equation 1-4y^2=0 are y= 1/2 ,y=-1/2

Find the zeros of 1-4y^2=0

The zeros of 1-4y^2=0 are y= 1/2 ,y=-1/2

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1 - 4 y^{2} = 0

y = \frac{1}{2}, y = - \frac{1}{2}

Solution steps

1 - 4 y^{2} = 0

Move

1

to the right side

- 4 y^{2} = - 1

Divide both sides by

- 4

y^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{1}{4}, y = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

y = \frac{1}{2}, y = - \frac{1}{2}

(x + 1)^{2} = 1

x^{3} - 3 x + 2

3 x^{2} + 12 x + 6 = 0

a^{3} + 125

\frac{3 x - 3}{5} + \frac{x + 3}{3} = 6

What are the solutions to the equation 1-4y^2=0 ?
The solutions to the equation 1-4y^2=0 are y= 1/2 ,y=-1/2
Find the zeros of 1-4y^2=0
The zeros of 1-4y^2=0 are y= 1/2 ,y=-1/2