What is log_{4}(x+1)+log_{4}(x)-4log_{4}(4) ?

The solution to log_{4}(x+1)+log_{4}(x)-4log_{4}(4) is log_{4}((x+1)x)-4

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simplify log_{4}(x+1)+log_{4}(x)-4log_{4}(4)

simplify

lo g_{4} (x + 1) + lo g_{4} (x) - 4 lo g_{4} (4)

lo g_{4} ((x + 1) x) - 4

Solution steps

lo g_{4} (x + 1) + lo g_{4} (x) - 4 lo g_{4} (4)

4 lo g_{4} (4) = 4

= lo g_{4} (x + 1) + lo g_{4} (x) - 4

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{4} (x + 1) + lo g_{4} (x) = lo g_{4} ((x + 1) x)

= lo g_{4} ((x + 1) x) - 4

3 ln (x) + \frac{1}{2} ln (y) - 4 ln (z)

lo g_{10} (x + 2) + lo g_{10} (x - 1)

lo g_{b} (\frac{7}{6})

ln (\frac{x ^{2} x ^{2} - 1}{e ^{x}})

\frac{1}{3} lo g_{b} (x) + 4 lo g_{b} (y) - 2 lo g_{b} (x)

What is log_{4}(x+1)+log_{4}(x)-4log_{4}(4) ?
The solution to log_{4}(x+1)+log_{4}(x)-4log_{4}(4) is log_{4}((x+1)x)-4