What is log_{b}(x)+log_{b}(x+2)-log_{b}(8) ?

The solution to log_{b}(x)+log_{b}(x+2)-log_{b}(8) is log_{b}((x(x+2))/8)

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simplify log_{b}(x)+log_{b}(x+2)-log_{b}(8)

simplify

lo g_{b} (x) + lo g_{b} (x + 2) - lo g_{b} (8)

lo g_{b} (\frac{x ( x + 2 )}{8})

Solution steps

lo g_{b} (x) + lo g_{b} (x + 2) - lo g_{b} (8)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (x) + lo g_{b} (x + 2) = lo g_{b} (x (x + 2))

= lo g_{b} (x (x + 2)) - lo g_{b} (8)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{b} (x (x + 2)) - lo g_{b} (8) = lo g_{b} (\frac{x ( x + 2 )}{8})

= lo g_{b} (\frac{x ( x + 2 )}{8})

lo g_{5} (\frac{x ^{2}}{y ^{2} z ^{3}})

- lo g_{10} (3.5 \cdot 1 0^{- 5})

lo g_{10} (c) - 2 lo g_{10} (g)

lo g_{4} (7 x)

ln (\frac{3 ^{x} 6 ^{2 x}}{2 ^{4 x}})

What is log_{b}(x)+log_{b}(x+2)-log_{b}(8) ?
The solution to log_{b}(x)+log_{b}(x+2)-log_{b}(8) is log_{b}((x(x+2))/8)