What is log_{6}((16x^2)/(2x-4)) ?

The solution to log_{6}((16x^2)/(2x-4)) is 3log_{6}(2)+2log_{6}(x)-log_{6}(x-2)

Popular >

simplify log_{6}((16x^2)/(2x-4))

simplify

lo g_{6} (\frac{16 x ^{2}}{2 x - 4})

3 lo g_{6} (2) + 2 lo g_{6} (x) - lo g_{6} (x - 2)

Solution steps

lo g_{6} (\frac{16 x ^{2}}{2 x - 4})

Simplify

\frac{16 x ^{2}}{2 x - 4} : \frac{8 x ^{2}}{x - 2}

= lo g_{6} (\frac{8 x ^{2}}{x - 2})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{6} (\frac{8 x ^{2}}{x - 2}) = lo g_{6} (8 x^{2}) - lo g_{6} (x - 2)

= lo g_{6} (8 x^{2}) - lo g_{6} (x - 2)

Simplify

lo g_{6} (8 x^{2}) : 3 lo g_{6} (2) + 2 lo g_{6} (x)

= 3 lo g_{6} (2) + 2 lo g_{6} (x) - lo g_{6} (x - 2)

lo g_{7} (\frac{x ^{4}}{y ^{2}})

lo g_{2} (\frac{4}{x + 9})

lo g_{10} (y) + 2 lo g_{10} (z)

lo g_{10} (\frac{x ^{33} y ^{20}}{z ^{36}})

- lo g_{10} (1.76 \times 1 0^{- 5})

What is log_{6}((16x^2)/(2x-4)) ?
The solution to log_{6}((16x^2)/(2x-4)) is 3log_{6}(2)+2log_{6}(x)-log_{6}(x-2)