What is 3log_{12}(2)+1/3 log_{12}(8)-log_{12}(4) ?

The solution to 3log_{12}(2)+1/3 log_{12}(8)-log_{12}(4) is 2log_{12}(2)

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simplify 3log_{12}(2)+1/3 log_{12}(8)-log_{12}(4)

simplify

3 lo g_{12} (2) + \frac{1}{3} lo g_{12} (8) - lo g_{12} (4)

2 lo g_{12} (2)

Decimal Notation

0.55788 \dots

Solution steps

3 lo g_{12} (2) + \frac{1}{3} lo g_{12} (8) - lo g_{12} (4)

- lo g_{12} (4) = - 2 lo g_{12} (2)

= 3 lo g_{12} (2) + \frac{1}{3} lo g_{12} (8) - 2 lo g_{12} (2)

Add similar elements:

3 lo g_{12} (2) - 2 lo g_{12} (2) = lo g_{12} (2)

= lo g_{12} (2) + \frac{1}{3} lo g_{12} (8)

\frac{1}{3} lo g_{12} (8) = lo g_{12} (2)

= lo g_{12} (2) + lo g_{12} (2)

Add similar elements:

lo g_{12} (2) + lo g_{12} (2) = 2 lo g_{12} (2)

= 2 lo g_{12} (2)

- lo g_{10} (1.3 \times 1 0^{- 4})

ln (\frac{1}{130})

lo g_{10} (8) - 2 lo g_{10} (6) + lo g_{10} (3)

lo g_{a} (6 x y^{5} z^{4})

What is 3log_{12}(2)+1/3 log_{12}(8)-log_{12}(4) ?
The solution to 3log_{12}(2)+1/3 log_{12}(8)-log_{12}(4) is 2log_{12}(2)