What is 2(p^{2/3}q^{1/3})^{-3/4} ?

The solution to 2(p^{2/3}q^{1/3})^{-3/4} is 2/(p^{1/2)q^{1/4}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 2(p^{2/3}q^{1/3})^{-3/4}

simplify

2 (p^{\frac{2}{3}} q^{\frac{1}{3}})^{- \frac{3}{4}}

\frac{2}{p ^{\frac{1}{2}} q ^{\frac{1}{4}}}

Solution steps

2 (p^{\frac{2}{3}} q^{\frac{1}{3}})^{- \frac{3}{4}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(p^{\frac{2}{3}} q^{\frac{1}{3}})^{- \frac{3}{4}} = \frac{1}{( p ^{\frac{2}{3}} q ^{\frac{1}{3}} ) ^{\frac{3}{4}}}

= 2 \cdot \frac{1}{( p ^{\frac{2}{3}} q ^{\frac{1}{3}} ) ^{\frac{3}{4}}}

Simplify

(p^{\frac{2}{3}} q^{\frac{1}{3}})^{\frac{3}{4}} : p^{\frac{1}{2}} q^{\frac{1}{4}}

= 2 \cdot \frac{1}{p ^{\frac{1}{2}} q ^{\frac{1}{4}}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 1}{p ^{\frac{1}{2}} q ^{\frac{1}{4}}}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2}{p ^{\frac{1}{2}} q ^{\frac{1}{4}}}

\frac{1}{\frac{9}{5}}

\frac{( x + 16 )}{3} = 3 x

\frac{( \frac{4}{- 2} ) - 2}{( \frac{4}{- 2} )}

x^{2} - 72 = 12 x

M - 9 = - 13

What is 2(p^{2/3}q^{1/3})^{-3/4} ?
The solution to 2(p^{2/3}q^{1/3})^{-3/4} is 2/(p^{1/2)q^{1/4}}