What is 3(2*log_{10}(a)-log_{10}(b)) ?

The solution to 3(2*log_{10}(a)-log_{10}(b)) is 6log_{10}(a)-3log_{10}(b)

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simplify 3(2*log_{10}(a)-log_{10}(b))

simplify

3 (2 \cdot lo g_{10} (a) - lo g_{10} (b))

6 lo g_{10} (a) - 3 lo g_{10} (b)

Solution steps

3 (2 lo g_{10} (a) - lo g_{10} (b))

Apply the distributive law:

a (b - c) = ab - a c

3 (2 lo g_{10} (a) - lo g_{10} (b)) = 3 \cdot 2 lo g_{10} (a) - 3 lo g_{10} (b)

= 3 \cdot 2 lo g_{10} (a) - 3 lo g_{10} (b)

Multiply the numbers:

3 \cdot 2 = 6

= 6 lo g_{10} (a) - 3 lo g_{10} (b)

lo g_{8} (\frac{x y ^{5}}{z ^{6}})

6 ln (x) - \frac{1}{8} ln (y)

- lo g_{10} (4 \times 1 0^{- 5})

6 ln (x) + 5 ln (y) - 4 ln (z)

lo g_{b} (x^{3})

What is 3(2*log_{10}(a)-log_{10}(b)) ?
The solution to 3(2*log_{10}(a)-log_{10}(b)) is 6log_{10}(a)-3log_{10}(b)