What is log_{5}(2)-log_{5}(t) ?

The solution to log_{5}(2)-log_{5}(t) is log_{5}(2/t)

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simplify log_{5}(2)-log_{5}(t)

simplify

lo g_{5} (2) - lo g_{5} (t)

lo g_{5} (\frac{2}{t})

Solution steps

lo g_{5} (2) - lo g_{5} (t)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{5} (2) - lo g_{5} (t) = lo g_{5} (\frac{2}{t})

= lo g_{5} (\frac{2}{t})

lo g_{8} (k^{2} - 64) - lo g_{8} (k) - 8

5 ln (x) + 4 ln (y) - 6 ln (z)

lo g_{10} (19 x)

lo g_{a} (m) + lo g_{a} (j) + lo g_{a} (r)

ln (7) - ln (5)

What is log_{5}(2)-log_{5}(t) ?
The solution to log_{5}(2)-log_{5}(t) is log_{5}(2/t)