What is log_{8}(k^2-64)-log_{8}(k)-8 ?

The solution to log_{8}(k^2-64)-log_{8}(k)-8 is log_{8}((k^2-64)/k)-8

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simplify log_{8}(k^2-64)-log_{8}(k)-8

simplify

lo g_{8} (k^{2} - 64) - lo g_{8} (k) - 8

lo g_{8} (\frac{k ^{2} - 64}{k}) - 8

Solution steps

lo g_{8} (k^{2} - 64) - lo g_{8} (k) - 8

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{8} (k^{2} - 64) - lo g_{8} (k) = lo g_{8} (\frac{k ^{2} - 64}{k})

= lo g_{8} (\frac{k ^{2} - 64}{k}) - 8

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What is log_{8}(k^2-64)-log_{8}(k)-8 ?
The solution to log_{8}(k^2-64)-log_{8}(k)-8 is log_{8}((k^2-64)/k)-8