What is the domain of f(x)=ln((3^x6^{3x})/(2^{3x)}) ?

The domain of f(x)=ln((3^x6^{3x})/(2^{3x)}) is -infinity <x<infinity

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domain of f(x)=ln((3^x6^{3x})/(2^{3x)})

domain

f (x) = ln (\frac{3 ^{x} 6 ^{3 x}}{2 ^{3 x}})

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{1}{2} lo g_{10} (x) - lo g_{10} (2) - 7 lo g_{10} (m)

\frac{2 ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

f (x) = lo g_{10} (2 x + 9) - lo g_{10} (x)

lo g_{\frac{1}{4}} (16 z (x^{3} - 27))

\frac{1}{2} ln 3 + e^{8} - ln (2)

What is the domain of f(x)=ln((3^x6^{3x})/(2^{3x)}) ?
The domain of f(x)=ln((3^x6^{3x})/(2^{3x)}) is -infinity <x<infinity