What is log_{10}(2x+9)-log_{10}(x) ?

The solution to log_{10}(2x+9)-log_{10}(x) is log_{10}((2x+9)/x)

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simplify log_{10}(2x+9)-log_{10}(x)

simplify

lo g_{10} (2 x + 9) - lo g_{10} (x)

lo g_{10} (\frac{2 x + 9}{x})

Solution steps

lo g_{10} (2 x + 9) - lo g_{10} (x)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (2 x + 9) - lo g_{10} (x) = lo g_{10} (\frac{2 x + 9}{x})

= lo g_{10} (\frac{2 x + 9}{x})

lo g_{\frac{1}{4}} (16 z (x^{3} - 27))

\frac{1}{2} ln 3 + e^{8} - ln (2)

lo g_{z} (\frac{2 x}{3})

- lo g_{10} (3 \cdot 1 0^{- 3})

What is log_{10}(2x+9)-log_{10}(x) ?
The solution to log_{10}(2x+9)-log_{10}(x) is log_{10}((2x+9)/x)