What is log_{7}(x+1)-log_{7}(1/(x+1)) ?

The solution to log_{7}(x+1)-log_{7}(1/(x+1)) is 2log_{7}(x+1)

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simplify log_{7}(x+1)-log_{7}(1/(x+1))

simplify

lo g_{7} (x + 1) - lo g_{7} (\frac{1}{x + 1})

2 lo g_{7} (x + 1)

Solution steps

lo g_{7} (x + 1) - lo g_{7} (\frac{1}{x + 1})

Simplify

lo g_{7} (\frac{1}{x + 1}) : - lo g_{7} (x + 1)

= lo g_{7} (x + 1) - (- lo g_{7} (x + 1))

Apply rule:

a - (- b) = a + b

lo g_{7} (x + 1) - (- lo g_{7} (x + 1)) = lo g_{7} (x + 1) + lo g_{7} (x + 1)

= lo g_{7} (x + 1) + lo g_{7} (x + 1)

Add similar elements:

lo g_{7} (x + 1) + lo g_{7} (x + 1) = 2 lo g_{7} (x + 1)

= 2 lo g_{7} (x + 1)

ln (3 ab \cdot 5 c)

lo g_{7} (x) + lo g_{7} (x - 3) - 2

3 ln (x) + 4 ln (y) - 5 ln (z)

lo g_{2} (3) - lo g_{2} (5)

What is log_{7}(x+1)-log_{7}(1/(x+1)) ?
The solution to log_{7}(x+1)-log_{7}(1/(x+1)) is 2log_{7}(x+1)