What is 1/(-0.032)ln(1/2) ?

The solution to 1/(-0.032)ln(1/2) is 1/(0.032)ln(2)

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simplify 1/(-0.032)ln(1/2)

simplify

\frac{1}{- 0.032} ln (\frac{1}{2})

\frac{1}{0.032} ln (2)

Decimal Notation

21.66084 \dots

Solution steps

\frac{1}{- 0.032} ln (\frac{1}{2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1}{2}) = ln (1) - ln (2)

= \frac{1}{- 0.032} (ln (1) - ln (2))

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{1}{0.032} (ln (1) - ln (2))

Apply log rule:

lo g_{a} (1) = 0

= - \frac{1}{0.032} (- ln (2) + 0)

0 - ln (2) = - ln (2)

= - \frac{1}{0.032} (- ln (2))

Apply rule

- (- a) = a

= \frac{1}{0.032} ln (2)

4 lo g_{b} (x) + 7 lo g_{b} (z)

ln (4 i)

ln (b) + 2 ln (c) - 3 ln (d)

lo g_{b} (\frac{x ^{3} \cdot y}{z ^{2}})

4 lo g_{b} (y) + 7 lo g_{b} (z)