What is 2log_{10}(3)+log_{10}(8) ?

The solution to 2log_{10}(3)+log_{10}(8) is log_{10}(72)

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simplify 2log_{10}(3)+log_{10}(8)

simplify

2 lo g_{10} (3) + lo g_{10} (8)

lo g_{10} (72)

Decimal Notation

1.85733 \dots

Solution steps

2 lo g_{10} (3) + lo g_{10} (8)

Apply log rule:

b \cdot lo g_{a} (x) = lo g_{a} (x^{b})

2 lo g_{10} (3) = lo g_{10} (3^{2})

= lo g_{10} (3^{2}) + lo g_{10} (8)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (3^{2}) + lo g_{10} (8) = lo g_{10} (3^{2} \cdot 8)

= lo g_{10} (3^{2} \cdot 8)

3^{2} \cdot 8 = 72

= lo g_{10} (72)

2 lo g_{10} (3) + lo g_{10} (5)

lo g_{10} (p) - 3 lo g_{10} (q) - \frac{1}{2} lo g_{10} (n)

lo g_{10} \frac{m}{( \frac{p}{q} )}

20 ln (\frac{1400}{1400 + 100 ( 30 )}) + 9.8 (30)

8 lo g_{3} (x) - 2 lo g_{3} (z) - 7 lo g_{3} (y)

What is 2log_{10}(3)+log_{10}(8) ?
The solution to 2log_{10}(3)+log_{10}(8) is log_{10}(72)