What is (log_{10}(6)+log_{10}(4))-log_{10}(3) ?

The solution to (log_{10}(6)+log_{10}(4))-log_{10}(3) is 3log_{10}(2)

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simplify (log_{10}(6)+log_{10}(4))-log_{10}(3)

simplify

(lo g_{10} (6) + lo g_{10} (4)) - lo g_{10} (3)

3 lo g_{10} (2)

Decimal Notation

0.90308 \dots

Solution steps

(lo g_{10} (6) + lo g_{10} (4)) - lo g_{10} (3)

Apply rule:

(a) = a

(lo g_{10} (6) + lo g_{10} (4)) = lo g_{10} (6) + lo g_{10} (4)

= lo g_{10} (6) + lo g_{10} (4) - lo g_{10} (3)

lo g_{10} (6) - lo g_{10} (3) = lo g_{10} (2)

= lo g_{10} (2) + lo g_{10} (4)

lo g_{10} (4) = 2 lo g_{10} (2)

= lo g_{10} (2) + 2 lo g_{10} (2)

Add similar elements:

lo g_{10} (2) + 2 lo g_{10} (2) = 3 lo g_{10} (2)

= 3 lo g_{10} (2)

2 lo g_{10} (5) - 6 lo g_{10} (3)

ln (x^{2}) - ln (x)

(\frac{1}{e})^{2} lo g_{3} (\frac{1}{e})

4 lo g_{10} (3) + 1 lo g_{10} (x)

lo g_{4} (\frac{x ^{2} y}{z})

What is (log_{10}(6)+log_{10}(4))-log_{10}(3) ?
The solution to (log_{10}(6)+log_{10}(4))-log_{10}(3) is 3log_{10}(2)