What is 1/2 log_{3}(8)+1/2 log_{3}(18)-1 ?

The solution to 1/2 log_{3}(8)+1/2 log_{3}(18)-1 is log_{3}(12)-1

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simplify 1/2 log_{3}(8)+1/2 log_{3}(18)-1

simplify

\frac{1}{2} lo g_{3} (8) + \frac{1}{2} lo g_{3} (18) - 1

lo g_{3} (12) - 1

Decimal Notation

1.26185 \dots

Solution steps

\frac{1}{2} lo g_{3} (8) + \frac{1}{2} lo g_{3} (18) - 1

\frac{1}{2} lo g_{3} (8) = lo g_{3} (8^{\frac{1}{2}})

\frac{1}{2} lo g_{3} (18) = lo g_{3} (1 8^{\frac{1}{2}})

= lo g_{3} (8^{\frac{1}{2}}) + lo g_{3} (1 8^{\frac{1}{2}}) - 1

lo g_{3} (8^{\frac{1}{2}}) + lo g_{3} (1 8^{\frac{1}{2}}) = lo g_{3} (12)

= lo g_{3} (12) - 1

lo g_{m} (a b^{2} c^{3})

- lo g_{10} (1.32 \cdot 1 0^{- 3})

lo g_{10} (10 a)

5 ln (x) - \frac{1}{5} ln (y)

- (\frac{2}{14}) lo g_{2} (\frac{2}{14}) - (\frac{3}{14}) lo g_{2} (\frac{3}{14})

What is 1/2 log_{3}(8)+1/2 log_{3}(18)-1 ?
The solution to 1/2 log_{3}(8)+1/2 log_{3}(18)-1 is log_{3}(12)-1