What is expand log_{2}((2x+1)/(x-5)) ?

The solution to expand log_{2}((2x+1)/(x-5)) is log_{2}(2x+1)-log_{2}(x-5)

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expand log_{2}((2x+1)/(x-5))

expand

lo g_{2} (\frac{2 x + 1}{x - 5})

lo g_{2} (2 x + 1) - lo g_{2} (x - 5)

Solution steps

lo g_{2} (\frac{2 x + 1}{x - 5})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{2} (\frac{2 x + 1}{x - 5}) = lo g_{2} (2 x + 1) - lo g_{2} (x - 5)

= lo g_{2} (2 x + 1) - lo g_{2} (x - 5)

5 lo g_{10} (8) + 2 lo g_{10} (x)

lo g_{6} (\frac{x y}{z t})

\frac{1}{3} ln (a^{2} b^{4})

lo g_{10} (0.5) + lo g_{10} (98)

lo g_{3} (9 (x^{2} - 9))

What is expand log_{2}((2x+1)/(x-5)) ?
The solution to expand log_{2}((2x+1)/(x-5)) is log_{2}(2x+1)-log_{2}(x-5)