What is log_{10}(6)-2log_{10}(y) ?

The solution to log_{10}(6)-2log_{10}(y) is log_{10}(6/(y^2))

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simplify log_{10}(6)-2log_{10}(y)

simplify

lo g_{10} (6) - 2 lo g_{10} (y)

lo g_{10} (\frac{6}{y ^{2}})

Solution steps

lo g_{10} (6) - 2 lo g_{10} (y)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (y) = lo g_{10} (y^{2})

= lo g_{10} (6) - lo g_{10} (y^{2})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (6) - lo g_{10} (y^{2}) = lo g_{10} (\frac{6}{y ^{2}})

= lo g_{10} (\frac{6}{y ^{2}})

lo g_{b} (\frac{x ^{2}}{y z ^{2}})

lo g_{b} (6) - lo g_{b} (3)

lo g_{7} (3 x) - lo g_{7} (9 x) + lo g_{7} (6 y)

3 [lo g_{10} (a) + lo g_{10} (a + 1)] - lo g_{10} (b)

\frac{1}{2} ln (\frac{1 + \frac{2}{2}}{1 - \frac{2}{2}})

What is log_{10}(6)-2log_{10}(y) ?
The solution to log_{10}(6)-2log_{10}(y) is log_{10}(6/(y^2))