What is expand log_{5}((x-1)^2)(4x) ?

The solution to expand log_{5}((x-1)^2)(4x) is 8xlog_{5}(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand log_{5}((x-1)^2)(4x)

expand

lo g_{5} ((x - 1)^{2}) (4 x)

8 x lo g_{5} (x - 1)

Solution steps

lo g_{5} ((x - 1)^{2}) (4 x)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{5} ((x - 1)^{2}) = 2 lo g_{5} (x - 1)

= 2 lo g_{5} (x - 1) \cdot 4 x

Multiply the numbers:

2 \cdot 4 = 8

= 8 x lo g_{5} (x - 1)

lo g_{10} (\frac{s}{t})

ln (\frac{4 w}{7})

ln (x) + ln (1 - x)

lo g_{10} (z) + lo g_{10} (11 y)

What is expand log_{5}((x-1)^2)(4x) ?
The solution to expand log_{5}((x-1)^2)(4x) is 8xlog_{5}(x-1)