What is log_{10}(x^2-7x-8)-log_{10}(x^2-1) ?

The solution to log_{10}(x^2-7x-8)-log_{10}(x^2-1) is log_{10}((x-8)/(x-1))

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simplify log_{10}(x^2-7x-8)-log_{10}(x^2-1)

simplify

lo g_{10} (x^{2} - 7 x - 8) - lo g_{10} (x^{2} - 1)

lo g_{10} (\frac{x - 8}{x - 1})

Solution steps

lo g_{10} (x^{2} - 7 x - 8) - lo g_{10} (x^{2} - 1)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (x^{2} - 7 x - 8) - lo g_{10} (x^{2} - 1) = lo g_{10} (\frac{x ^{2} - 7 x - 8}{x ^{2} - 1})

= lo g_{10} (\frac{x ^{2} - 7 x - 8}{x ^{2} - 1})

Simplify

\frac{x ^{2} - 7 x - 8}{x ^{2} - 1} : \frac{x - 8}{x - 1}

= lo g_{10} (\frac{x - 8}{x - 1})

ln (\frac{( c ^{1 - n} m ^{n} ) ^{1 - l}}{1 - l})

20 lo g_{10} (2) + 40 lo g_{10} (0.04)

lo g_{3} (\frac{1}{16}) - 1

lo g_{10} (\frac{x}{2})

What is log_{10}(x^2-7x-8)-log_{10}(x^2-1) ?
The solution to log_{10}(x^2-7x-8)-log_{10}(x^2-1) is log_{10}((x-8)/(x-1))