What is log_{2}(3x)+log_{2}(4^4) ?

The solution to log_{2}(3x)+log_{2}(4^4) is log_{2}(3x)+8

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simplify log_{2}(3x)+log_{2}(4^4)

simplify

lo g_{2} (3 x) + lo g_{2} (4^{4})

lo g_{2} (3 x) + 8

Solution steps

lo g_{2} (3 x) + lo g_{2} (4^{4})

lo g_{2} (4^{4}) = 8

= lo g_{2} (3 x) + 8

\frac{ln ( 6 ) - ln ( 5 )}{4}

ln (\frac{7 x 1 + 6 x}{( x - 4 ) ^{4}})

lo g_{3} ((u^{4} v)^{6})

ln (\frac{1}{2 ^{n}})

2 lo g_{5} (3) - \frac{1}{2} lo g_{5} (4) + lo g_{5} (8)

What is log_{2}(3x)+log_{2}(4^4) ?
The solution to log_{2}(3x)+log_{2}(4^4) is log_{2}(3x)+8