What is 7(log_{4}(3)+log_{4}(y))-log_{4}(2) ?

The solution to 7(log_{4}(3)+log_{4}(y))-log_{4}(2) is 7log_{4}(3y)-1/2

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simplify 7(log_{4}(3)+log_{4}(y))-log_{4}(2)

simplify

7 (lo g_{4} (3) + lo g_{4} (y)) - lo g_{4} (2)

7 lo g_{4} (3 y) - \frac{1}{2}

Solution steps

7 (lo g_{4} (3) + lo g_{4} (y)) - lo g_{4} (2)

lo g_{4} (3) + lo g_{4} (y) = lo g_{4} (3 y)

lo g_{4} (2) = \frac{1}{2}

= 7 lo g_{4} (3 y) - \frac{1}{2}

lo g_{10} (\frac{x}{y ^{7}})

lo g_{10} (1.54 x) lo g_{10} (1.02)

lo g_{d} (u^{8} v^{3})

ln (4 \cdot 3)

2 lo g_{3} (3 x)

What is 7(log_{4}(3)+log_{4}(y))-log_{4}(2) ?
The solution to 7(log_{4}(3)+log_{4}(y))-log_{4}(2) is 7log_{4}(3y)-1/2