What is log_{10}(1.54x)log_{10}(1.02) ?

The solution to log_{10}(1.54x)log_{10}(1.02) is (log_{10}(154)+log_{10}(x)-2)(log_{10}(102)-2)

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simplify log_{10}(1.54x)log_{10}(1.02)

simplify

lo g_{10} (1.54 x) lo g_{10} (1.02)

(lo g_{10} (154) + lo g_{10} (x) - 2) (lo g_{10} (102) - 2)

Solution steps

lo g_{10} (1.54 x) lo g_{10} (1.02)

lo g_{10} (1.54 x) = lo g_{10} (154 x) - 2

lo g_{10} (1.02) = lo g_{10} (102) - 2

= (lo g_{10} (154 x) - 2) (lo g_{10} (102) - 2)

Simplify

lo g_{10} (154 x) : lo g_{10} (154) + lo g_{10} (x)

= (lo g_{10} (154) + lo g_{10} (x) - 2) (lo g_{10} (102) - 2)

lo g_{d} (u^{8} v^{3})

ln (4 \cdot 3)

2 lo g_{3} (3 x)

- lo g_{10} (3.1 \cdot 1 0^{- 6})

What is log_{10}(1.54x)log_{10}(1.02) ?
The solution to log_{10}(1.54x)log_{10}(1.02) is (log_{10}(154)+log_{10}(x)-2)(log_{10}(102)-2)