What is ln((1+i)/(sqrt(2))) ?

The solution to ln((1+i)/(sqrt(2))) is ln(1+i)-1/2 ln(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln((1+i)/(sqrt(2)))

simplify

ln (\frac{1 + i}{2})

ln (1 + i) - \frac{1}{2} ln (2)

Solution steps

ln (\frac{1 + i}{2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1 + i}{2}) = ln (1 + i) - ln (2)

= ln (1 + i) - ln (2)

ln (2) = \frac{1}{2} ln (2)

= ln (1 + i) - \frac{1}{2} ln (2)

lo g_{\frac{1}{3}} (\frac{x ^{2} - x - 6}{2}) + x + 1

lo g_{10} (r^{2} s) - lo g_{10} (r s^{2}) + 1

lo g_{5} (x^{2}) - lo g_{5} (2)

lo g_{3} (\frac{1}{2}) - lo g_{9} (\frac{1}{2})

lo g_{2} (\frac{i}{j s})

What is ln((1+i)/(sqrt(2))) ?
The solution to ln((1+i)/(sqrt(2))) is ln(1+i)-1/2 ln(2)