What is log_{2}(i/(js)) ?

The solution to log_{2}(i/(js)) is log_{2}(i)-log_{2}(j)-log_{2}(s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{2}(i/(js))

simplify

lo g_{2} (\frac{i}{j s})

lo g_{2} (i) - lo g_{2} (j) - lo g_{2} (s)

Solution steps

lo g_{2} (\frac{i}{j s})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{2} (\frac{i}{j s}) = lo g_{2} (i) - lo g_{2} (j s)

= lo g_{2} (i) - lo g_{2} (j s)

Simplify

lo g_{2} (j s) : lo g_{2} (j) + lo g_{2} (s)

= lo g_{2} (i) - (lo g_{2} (j) + lo g_{2} (s))

Apply the distributive law:

- (a + b) = - a - b

- (lo g_{2} (j) + lo g_{2} (s)) = - lo g_{2} (j) - lo g_{2} (s)

= lo g_{2} (i) - lo g_{2} (j) - lo g_{2} (s)

ln (\frac{u}{3} + 1) - ln (\frac{u}{3} - 1)

lo g_{7} (9 x)

lo g_{5} (\frac{x y}{z})

lo g_{10} (y) - 15 lo g_{10} (z)

6 lo g_{2} (x) + 12 lo g_{2} (y)

What is log_{2}(i/(js)) ?
The solution to log_{2}(i/(js)) is log_{2}(i)-log_{2}(j)-log_{2}(s)