What is log_{10}(1)+log_{10}(2)+log_{10}(3) ?

The solution to log_{10}(1)+log_{10}(2)+log_{10}(3) is log_{10}(6)

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simplify log_{10}(1)+log_{10}(2)+log_{10}(3)

simplify

lo g_{10} (1) + lo g_{10} (2) + lo g_{10} (3)

lo g_{10} (6)

Decimal Notation

0.77815 \dots

Solution steps

lo g_{10} (1) + lo g_{10} (2) + lo g_{10} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (1) + lo g_{10} (2) = lo g_{10} (1 \cdot 2)

= lo g_{10} (1 \cdot 2) + lo g_{10} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (1 \cdot 2) + lo g_{10} (3) = lo g_{10} (1 \cdot 2 \cdot 3)

= lo g_{10} (1 \cdot 2 \cdot 3)

Multiply the numbers:

1 \cdot 2 \cdot 3 = 6

= lo g_{10} (6)

lo g_{10} (2.3) - lo g_{10} (3.1)

lo g_{4} (x) + lo g_{4} (x - 3)

lo g_{10} (x) - 3 lo g_{10} (y) + 5 lo g_{10} (z)

3 lo g_{10} (x) - 5 lo g_{10} (y)

lo g_{b} (\frac{p ^{2} q ^{5}}{m ^{5} b ^{7}})

What is log_{10}(1)+log_{10}(2)+log_{10}(3) ?
The solution to log_{10}(1)+log_{10}(2)+log_{10}(3) is log_{10}(6)