What is log_{10}(x)+log_{10}(x-2)-log_{4}(x) ?

The solution to log_{10}(x)+log_{10}(x-2)-log_{4}(x) is log_{10}(x(x-2))-log_{4}(x)

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simplify log_{10}(x)+log_{10}(x-2)-log_{4}(x)

simplify

lo g_{10} (x) + lo g_{10} (x - 2) - lo g_{4} (x)

lo g_{10} (x (x - 2)) - lo g_{4} (x)

Solution steps

lo g_{10} (x) + lo g_{10} (x - 2) - lo g_{4} (x)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (x) + lo g_{10} (x - 2) = lo g_{10} (x (x - 2))

= lo g_{10} (x (x - 2)) - lo g_{4} (x)

4 lo g_{5} (u) + 5 lo g_{5} (v)

lo g_{10} (4 x^{2})

lo g_{4} (\frac{1}{6}) + lo g_{\frac{1}{3}} (81)

lo g_{3} (\frac{x}{x - 2})

What is log_{10}(x)+log_{10}(x-2)-log_{4}(x) ?
The solution to log_{10}(x)+log_{10}(x-2)-log_{4}(x) is log_{10}(x(x-2))-log_{4}(x)