What is log_{10}(18)-log_{10}(6) ?

The solution to log_{10}(18)-log_{10}(6) is log_{10}(3)

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simplify log_{10}(18)-log_{10}(6)

simplify

lo g_{10} (18) - lo g_{10} (6)

lo g_{10} (3)

Decimal Notation

0.47712 \dots

Solution steps

lo g_{10} (18) - lo g_{10} (6)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (18) - lo g_{10} (6) = lo g_{10} (\frac{18}{6})

= lo g_{10} (\frac{18}{6})

Divide the numbers:

\frac{18}{6} = 3

= lo g_{10} (3)

lo g_{3} (2) + lo g_{3} (13)

2 lo g_{5} (x) - lo g_{5} (y) - \frac{1}{2} lo g_{5} (z)

lo g_{10} (\frac{1000 c ^{5}}{2 d ^{4}})

lo g_{2} (2000) - lo g_{2} (150)

lo g_{5} (4) + lo g_{5} (6)

What is log_{10}(18)-log_{10}(6) ?
The solution to log_{10}(18)-log_{10}(6) is log_{10}(3)