What is log_{10}(A)+log_{10}(B)-log_{10}(1/C) ?

The solution to log_{10}(A)+log_{10}(B)-log_{10}(1/C) is log_{10}(ABC)

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simplify log_{10}(A)+log_{10}(B)-log_{10}(1/C)

simplify

lo g_{10} (A) + lo g_{10} (B) - lo g_{10} (\frac{1}{C})

lo g_{10} (A BC)

Solution steps

lo g_{10} (A) + lo g_{10} (B) - lo g_{10} (\frac{1}{C})

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (A) + lo g_{10} (B) = lo g_{10} (A B)

= lo g_{10} (A B) - lo g_{10} (\frac{1}{C})

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (A B) - lo g_{10} (\frac{1}{C}) = lo g_{10} (\frac{A B}{\frac{1}{C}})

= lo g_{10} (\frac{A B}{\frac{1}{C}})

Simplify

\frac{A B}{\frac{1}{C}} : A BC

= lo g_{10} (A BC)

lo g_{7} (\frac{49 m ^{6}}{k ^{3}})

3.79588 + lo g_{10} (\frac{0.2}{0.5})

lo g_{10} (2 c d)

3 (ln (x) - 2 ln (x^{2} + 1)) + 2 ln (5)

lo g_{8} (4) + 2 lo g_{8} (x)

What is log_{10}(A)+log_{10}(B)-log_{10}(1/C) ?
The solution to log_{10}(A)+log_{10}(B)-log_{10}(1/C) is log_{10}(ABC)