What is log_{2x-1}(4.5x) ?

The solution to log_{2x-1}(4.5x) is log_{2x-1}(4.5)+log_{2x-1}(x)

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simplify log_{2x-1}(4.5x)

simplify

lo g_{2 x - 1} (4.5 x)

lo g_{2 x - 1} (4.5) + lo g_{2 x - 1} (x)

Solution steps

lo g_{2 x - 1} (4.5 x)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{2 x - 1} (4.5 x) = lo g_{2 x - 1} (4.5) + lo g_{2 x - 1} (x)

= lo g_{2 x - 1} (4.5) + lo g_{2 x - 1} (x)

lo g_{10} (\frac{x}{1 0 ^{- 12}})

ln (1 \cdot 5)

lo g_{5} (7) + lo g_{5} (6)

7 lo g_{b} (y) - \frac{1}{3} lo g_{b} (x) + 5 lo g_{b} (z)

- lo g_{10} (9 \times 1 0^{- 5})

What is log_{2x-1}(4.5x) ?
The solution to log_{2x-1}(4.5x) is log_{2x-1}(4.5)+log_{2x-1}(x)