What is log_{10}((9b)/(10)) ?

The solution to log_{10}((9b)/(10)) is 2log_{10}(3)+log_{10}(b)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}((9b)/(10))

simplify

lo g_{10} (\frac{9 b}{10})

2 lo g_{10} (3) + lo g_{10} (b) - 1

Solution steps

lo g_{10} (\frac{9 b}{10})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{9 b}{10}) = lo g_{10} (9 b) - lo g_{10} (10)

= lo g_{10} (9 b) - lo g_{10} (10)

lo g_{10} (9 b) = 2 lo g_{10} (3) + lo g_{10} (b)

lo g_{10} (10) = 1

= 2 lo g_{10} (3) + lo g_{10} (b) - 1

3 ln (3) - 3 ln (2)

lo g_{10} (\frac{x ^{5} + y}{1000})

lo g_{3} (x^{2} y^{2})

ln (a^{\frac{3}{2}} b^{\frac{1}{2}}) - 1

ln (6 e^{x})

What is log_{10}((9b)/(10)) ?
The solution to log_{10}((9b)/(10)) is 2log_{10}(3)+log_{10}(b)-1