What is log_{b}(6)+log_{b}(10) ?

The solution to log_{b}(6)+log_{b}(10) is log_{b}(60)

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simplify log_{b}(6)+log_{b}(10)

simplify

lo g_{b} (6) + lo g_{b} (10)

lo g_{b} (60)

Solution steps

lo g_{b} (6) + lo g_{b} (10)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (6) + lo g_{b} (10) = lo g_{b} (6 \cdot 10)

= lo g_{b} (6 \cdot 10)

Multiply the numbers:

6 \cdot 10 = 60

= lo g_{b} (60)

lo g_{10} (\frac{15}{5}) + lo g_{10} (\frac{2}{5})

- (\frac{1}{7}) lo g_{2} (\frac{1}{7}) - (\frac{6}{7}) lo g_{2} (\frac{6}{7})

\frac{1}{3} lo g_{c} (x) + 3 lo g_{c} (y) - 2 lo g_{c} (x)

- lo g_{10} (5.2 \cdot 1 0^{- 8})

What is log_{b}(6)+log_{b}(10) ?
The solution to log_{b}(6)+log_{b}(10) is log_{b}(60)