What is log_{13}((\sqrt[8]{11})/(y^2x)) ?

The solution to log_{13}((\sqrt[8]{11})/(y^2x)) is log_{13}(\sqrt[8]{11})-2log_{13}(y)-log_{13}(x)

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simplify log_{13}((\sqrt[8]{11})/(y^2x))

simplify

Solution steps

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

Simplify

lo g_{13} (y^{2} x) : 2 lo g_{13} (y) + lo g_{13} (x)

Apply the distributive law:

- (a + b) = - a - b

- (2 lo g_{13} (y) + lo g_{13} (x)) = - 2 lo g_{13} (y) - lo g_{13} (x)

3 lo g_{5} (x - 1) - lo g_{5} (3 - 6 x)

ln (x) + ln (x - 4) - 2 ln (x + 1)

\frac{1}{2} (lo g_{10} (b) - lo g_{10} (c))

lo g_{10} (5 bm)

6 ln (x + 7) - ln (x)

What is log_{13}((\sqrt[8]{11})/(y^2x)) ?
The solution to log_{13}((\sqrt[8]{11})/(y^2x)) is log_{13}(\sqrt[8]{11})-2log_{13}(y)-log_{13}(x)