What is 1/2 (log_{10}(b)-log_{10}(c)) ?

The solution to 1/2 (log_{10}(b)-log_{10}(c)) is (log_{10}(b/c))/2

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simplify 1/2 (log_{10}(b)-log_{10}(c))

simplify

\frac{1}{2} (lo g_{10} (b) - lo g_{10} (c))

\frac{lo g _{10} ( \frac{b}{c} )}{2}

Solution steps

\frac{1}{2} (lo g_{10} (b) - lo g_{10} (c))

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (b) - lo g_{10} (c) = lo g_{10} (\frac{b}{c})

= \frac{1}{2} lo g_{10} (\frac{b}{c})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot lo g _{10} ( \frac{b}{c} )}{2}

Apply rule:

1 \cdot a = a

1 \cdot lo g_{10} (\frac{b}{c}) = lo g_{10} (\frac{b}{c})

= \frac{lo g _{10} ( \frac{b}{c} )}{2}

lo g_{10} (5 bm)

6 ln (x + 7) - ln (x)

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What is 1/2 (log_{10}(b)-log_{10}(c)) ?
The solution to 1/2 (log_{10}(b)-log_{10}(c)) is (log_{10}(b/c))/2