What is 2log_{10}(2)-log_{10}(3) ?

The solution to 2log_{10}(2)-log_{10}(3) is log_{10}(4/3)

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simplify 2log_{10}(2)-log_{10}(3)

simplify

2 lo g_{10} (2) - lo g_{10} (3)

lo g_{10} (\frac{4}{3})

Decimal Notation

0.12493 \dots

Solution steps

2 lo g_{10} (2) - lo g_{10} (3)

Apply log rule:

b \cdot lo g_{a} (x) = lo g_{a} (x^{b})

2 lo g_{10} (2) = lo g_{10} (2^{2})

= lo g_{10} (2^{2}) - lo g_{10} (3)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (2^{2}) - lo g_{10} (3) = lo g_{10} (\frac{2 ^{2}}{3})

= lo g_{10} (\frac{2 ^{2}}{3})

2^{2} = 4

= lo g_{10} (\frac{4}{3})

3 \cdot lo g_{10} (2) + lo g_{10} (x - 4)

\frac{( ln ( 300 ) - ln ( 700 ) )}{20}

ln (\frac{- 1}{- 5})

lo g_{2} (3) - lo g_{2} (7)

4 - lo g_{6} (36 y)

What is 2log_{10}(2)-log_{10}(3) ?
The solution to 2log_{10}(2)-log_{10}(3) is log_{10}(4/3)