What is log_{4}(2x+3)+log_{4}(2x+15) ?

The solution to log_{4}(2x+3)+log_{4}(2x+15) is log_{4}((2x+3)(2x+15))

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simplify log_{4}(2x+3)+log_{4}(2x+15)

simplify

lo g_{4} (2 x + 3) + lo g_{4} (2 x + 15)

lo g_{4} ((2 x + 3) (2 x + 15))

Solution steps

lo g_{4} (2 x + 3) + lo g_{4} (2 x + 15)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{4} (2 x + 3) + lo g_{4} (2 x + 15) = lo g_{4} ((2 x + 3) (2 x + 15))

= lo g_{4} ((2 x + 3) (2 x + 15))

ln (\frac{k ^{8}}{m ^{6}})

ln (- c x)

lo g_{7} (2) + 2 lo g_{7} (3)

\frac{1}{2} [ln (x + 3) + ln (x) - ln (x^{2} - 1)]

What is log_{4}(2x+3)+log_{4}(2x+15) ?
The solution to log_{4}(2x+3)+log_{4}(2x+15) is log_{4}((2x+3)(2x+15))